asyncio.TimeoutError: Operation Timed Out

asyncio.TimeoutError

Quick Answer

An async operation exceeded the specified timeout. Increase the timeout or investigate why the operation is slow.

Why This Happens

asyncio.wait_for() raises TimeoutError when an operation takes too long. This prevents indefinite waits but needs to be handled gracefully.

The Problem

async def main():
    result = await asyncio.wait_for(slow_op(), timeout=1.0)

The Fix

async def main():
    try:
        result = await asyncio.wait_for(slow_op(), timeout=1.0)
    except asyncio.TimeoutError:
        print('Timed out, using fallback')
        result = 'default'

Step-by-Step Fix

  1. 1

    Handle the timeout

    Wrap in try/except asyncio.TimeoutError.

  2. 2

    Increase timeout

    If the operation legitimately takes longer, increase the value.

  3. 3

    Investigate slow operations

    Profile to find why the operation is slow.

Got the actual stack trace?

Paste it into our free AI explainer to get the cause and the fix for your specific case — no signup, nothing to install.

Explain my error

Bugsly catches this automatically

Bugsly's AI analyzes this error pattern in real-time, explains what went wrong in plain English, and suggests the exact fix — before your users even report it.

Try Bugsly free