Why This Happens
Python raises NameError when you reference a name that does not exist in the current scope. Common causes include typos, using a variable before assignment, and forgetting imports. Python is case-sensitive.
The Problem
for i in range(10):
if i > 5:
result = i
print(result)The Fix
result = None
for i in range(10):
if i > 5:
result = i
print(result)Step-by-Step Fix
- 1
Check for typos
Python is case-sensitive: 'Result' and 'result' differ.
- 2
Initialize variables
Define variables before conditional blocks.
- 3
Check scope
Variables inside functions are not accessible outside.
Bugsly catches this automatically
Bugsly's AI analyzes this error pattern in real-time, explains what went wrong in plain English, and suggests the exact fix — before your users even report it.
Try Bugsly free